Oliver Heaviside and the theory of transmission linesPieter-Tjerk de Boer, PA3FWM firstname.lastname@example.org
(This is an adapted version of an article I wrote for the Dutch amateur radio magazine Electron, November 2021.)
An antenna cable is not just a piece of wire. Technically, it's called a "transmission line", with special properties such as its characteristic impedance. But transmission lines are quite a bit older than radio technology: they date back to the second half of the 19th century, in the form of (mostly submarine) telegraph cables. In this article we look at the principles and properties of transmission lines, with special emphasis on Oliver Heaviside's contribution to our knowledge of them.
Oliver HeavisideAfter secondary school, Oliver Heaviside (1850-1925) started working at the company which operated the submarine telegraph cable between Newcastle (UK) and Denmark. At first he worked as a telegraph operator, but soon he also got involved with the (electro)technical side of the telegraph systems. One of the things he noticed, was that when water leaked into a submarine cable and progressively short-circuited it, the signals did not just become weaker (as expected), but also clearer, less distorted.
In those days, electrical engineering was still in its infancy. Thanks to the work of physicists like Volta, Ampère, Ørsted and Faraday, there was a decent understanding of generating electrical currents and moving compass needles using an electromagnet. Together, that is enough for building a telegraph, at least in principle. But if one uses as very long cable, and tries to send dots and dashes at a high rate, it turned out to not work so well. There was little theoretical understanding of this, particularly among the more practically minded people who cobbled together telegraph systems.
Heaviside studied physics by himself, and stumbled on the books by James Clerk Maxwell. Maxwell's ideas about electromagnetism were, at that time, rather speculative and not widely accepted, but Heaviside got enthousiastic, studied them, and succesfully applied this theory to telegraph lines.
Thus, Heaviside, who never had studied at a university, rose from being a humble telegraph operator to a respected physicist. After quitting his job at the telegraph company at the age of 24, he never had another job. The rest of his life he lived in relative poverty while working on the theory. He became one of the so-called Maxwellians: a group of physicists who enhanced Maxwell's theory after his untimely death (in 1879 at the age of 48) and popularised it. One of Heaviside's achievements is that he converted Maxwell's twenty mathematical formulas into a more accessible set of just four, which nowadays are taught at all universities as "Maxwell's equations". If you want to learn more about this remarkable person, I recommend his biography .
Thomson's modelWilliam Thomson (later Lord Kelvin) attempted to describe what happens in a long telegraph cable. His model is sketched in the figure. He mentally chopped the cable into short pieces, each of which has some resistance and some capacitance. Next, he calculated what happens if at the left end one suddenly applies a voltage of say 1 volt. The graphs show the result, for a 4 km long cable having 0.1 ohm of resistance per meter, and 10 pF of capacitance per meter. The cable has been divided into 4 pieces of 1 km each, so each having 100 ohm and 10 nF. We see that the voltage on the first capacitor gradually increases to 1 volt: that's logical, as the capacitor gets charged via the first resistor. The voltage on the second capacitor also gradually increases to 1 volt, but slower: that makes sense, as it is charged from the first capacitor. And so on. At the right end of the cable, the voltage increases only very gradually, and this slow increases puts a limit on how quickly Morse code signs can be sent.
However, Thomson's model is wrong.
Heaviside's modelHeaviside realised that the inductance of the cable is also important. See the next figure: here we have replaced Thomson's resistors by inductors, of 1 µH per meter of cable length.
First have a look at the first set of graphs, marked as "4 sections". We see that the voltage on the first capacitor reaches the full 1 volt much earlier than in Thomson's model, and even overshoots. This is because once there is current flowing in an inductor, this current doesn't just stop when the voltage across the coil becomes lower. This faster increase of the voltage, and the fact that the current doesn't just stop, also causes the second capacitor to be charged earlier and faster than in Thomson's model, and so on.
Of course, modelling a 4 km long cable in just 4 pieces is not very realistic. For a better model, we could e.g. model it using 10 times as many pieces, each 10 times shorter (i.e., 40 pieces of 100 m each), each with 10 times less capacitance and inductance. The result is shown in the second set of graphs. The third set of graphs is for a yet 10 times finer modelling of the cable. The graphs now show the voltage at every 10th and every 100th capacitor, respectively; i.e., still at distances of 1, 2, 3 and 4 km from the start of the cable, like in the first set of graphs. We see that with the more refined model, the voltages increase faster and the overshoot takes less long.
The schematic with all those coils and capacitors resembles a low-pass filter, and indeed, we see that the voltages increase only gradually, hinting at the absence of high frequencies. When one partitions the model in ever smaller pieces, the inductances and capacitances become smaller and the filter's cut-off frequency becomes higher. If one mathematically takes the limit, eventually modelling the cable as consisting of infinitely many pieces, each having infinitely little inductance and capacitance, one gets an ever more accurate model. While doing so, the low-pass effect disappears, and the voltage jump from 0 to 1 volt is transmitted without distortion.
ImpedanceHeaviside's model also helps us to understand what the "impedance" of a cable is. At the left, suddenly a voltage of 1 volt is applied to the cable. The capacitors are as yet uncharged, so there's 1 volt across the first inductor, causing a gradually increasing current to flow. How large will that current become? That depends on the inductance: the more inductance, the slower the current increases. And it also depends on the capacitance: the more capacitance, the more charge needs to be supplied to charge it to 1 volt. When the capacitor has been charged to 1 volt (ignoring the overshoot), there will be 0 volts across the inductor, so the current through it will no longer change. The current doesn't be come 0, but remains constant, flows into the second inductor, charges the second capacitor, and so on.
And what happens when also the last capacitor has been charged? As noted above, the current through those inductors cannot just stop. If we "terminate" the cable in a resistor, as shown in the figure, then the current will flow through the resistor and cause a voltage drop across it. If the resistor has exactly the right value, then that voltage drop is exactly 1 volt. Then we reach a stable state: all capacitors are charged to 1 volt, across the coils there's no voltage, and a constant current flows from the source through the cable and the termination resistor.
If the termination resistor is too large, the voltage drop across it will be more than 1 volt, so the last capacitor will be charged to more than 1 volt. Via the last inductor a part of that charge will then flow back from the last to the second-to-last capacitor, from there to the third-last capacitor, and so on: we get a reflected wave. Something similar happens if the termination resistor is too small.
The value of the termination resistor which does not cause a reflection, is called the impedance of the cable. It turns out that this equals , where L and C are the inductance and capacitance per meter of cable length. Note that this formula matches what we already observed earlier: more L means less current and thus higher termination resistor needed to still drop 1 volt; similarly, more C means more current and thus lower termination resistor.
SpeedIn the previous figure, we effectively saw a wave move from left to right through the cable; the farther from the source, the later the voltage change arrives. How fast does this wave move? That also depends on the values of L and C. The larger the inductance L, the slower the current increases (at given voltage), so the longer it takes to charge the next capacitor. And the larger C, the longer it takes (at given current) to charge the capacitance. Heaviside showed that the speed equals
Does this mean that we can make a cable with any desired speed, simply by choosing L and C appropriately? Perhaps even faster than light? (Einstein already starts turning over in his grave.) No: it turns out that we have only limited freedom in choosing L and C. Changing the shape and size of the cable affects both L and C, and always such that the speed of light is never exceeded.
As an example, consider a coaxial cable.
If one makes the center conductor thinner, the capacitance between center conductor and
shield decreases, so by the formula one would expect the speed to increase.
Unfortunately, at the same time the inductance increases!
That's (among others) because making the center conductor thinner causes the currents
inside that center conductor to be closer together, and thus sense more of each other's
magnetic field (which, after all, is what causes (self)-inductance).
If we fill the cable with e.g. some plastic material, the capacitance increases while the
inductance remains the same. Then the speed decreases; this is generally described
as the "velocity factor" being less than 1.
Heaviside showed that losses do not just attenuate the signal, but also cause distortion.
In fact we already saw this in Thomson's model in the first figure:
the sudden increase of the voltage at the input of the cable, is distorted to something
that only rises slowsly, as it travels down the cable.
However, Heaviside also found out that this distortion disappears if the following
condition is satisfied: L/R = C/G.
If there is no loss, then R and G are both 0, so the condition is satisfied.
But a realistic cable usually has L/R much smaller than C/G,
because G, the leakage of the isolation, is almost zero (good isolation material),
and particularly in submarine cables, the capacitance is rather high.
In principle, we can improve such a cable in four ways to satisfy the condition:
Should we now also insert coils into our antenna cables to prevent distortion of our
No: firstly the distortion is negligible for relatively narrow-band signals;
and secondly, such coils would work as a low-pass filter, so our (high) frequencies
wouldn't get through anymore.
Loss and distortion
So far, we haven't included loss in the model, but a real cable does have loss due to resistances,
and Heaviside included this in his model, as sketched at the right.
There are two kinds of loss.
The first one is the resistance of the copper wire itself; to model this,
Heaviside included a resistance of R ohms per meter in series with each inductance.
The second one is the leakage of the capacitor's isolation, modelled as a parallel resistance 1/G.
(We write this as 1/G because this resistance is inversely proportional to the length;
the shorter the cable section, the less leakage, so the larger the leakage resistance.
Thus G itself, being the inverse of the resistance, is again directly proportional
to the length; it is expressed in Ω-1 per meter, also called Siemens per meter.)
 Basil Mahon: The forgotten genius of Oliver Heaviside -- A maverick of electrical science. 2017.
If we fill the cable with e.g. some plastic material, the capacitance increases while the inductance remains the same. Then the speed decreases; this is generally described as the "velocity factor" being less than 1.
Heaviside showed that losses do not just attenuate the signal, but also cause distortion. In fact we already saw this in Thomson's model in the first figure: the sudden increase of the voltage at the input of the cable, is distorted to something that only rises slowsly, as it travels down the cable.
However, Heaviside also found out that this distortion disappears if the following condition is satisfied: L/R = C/G. If there is no loss, then R and G are both 0, so the condition is satisfied. But a realistic cable usually has L/R much smaller than C/G, because G, the leakage of the isolation, is almost zero (good isolation material), and particularly in submarine cables, the capacitance is rather high. In principle, we can improve such a cable in four ways to satisfy the condition:
Should we now also insert coils into our antenna cables to prevent distortion of our radio signals? No: firstly the distortion is negligible for relatively narrow-band signals; and secondly, such coils would work as a low-pass filter, so our (high) frequencies wouldn't get through anymore.